What is the energy required for separation of an nucleus into four identical particles? (Nuclear mas — Nuclear Chemistry and Radioactivity Chemistry Question
Question
What is the energy required for separation of an $\text{O}^{16}$ nucleus into four identical particles? (Nuclear masses: $\text{O}^{16} = 15.9944 \text{ u}, \text{He}^4 = 4.0026 \text{ u}$)
Answer: A
💡 Solution & Explanation
The reaction is $\text{O}^{16} \to 4\text{He}^4$. Mass of products = $4 \times 4.0026 = 16.0104 \text{ u}$. Mass of reactant = $15.9944 \text{ u}$. Mass defect $\Delta m = 16.0104 - 15.9944 = 0.0160 \text{ u}$. Energy required $E = 0.0160 \times 931.5 \text{ MeV/u} = 14.904 \text{ MeV}$. Therefore, correct answer is A.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes