A proton and an -particle are accelerated through the same potential difference. The ratio of their — Atomic Structure Chemistry Question

💡 Solution & Explanation

Wavelength $\lambda = \frac{h}{\sqrt{2mqV}}$. Ratio $\frac{\lambda_p}{\lambda_\alpha} = \sqrt{\frac{m_\alpha q_\alpha}{m_p q_p}} = \sqrt{\frac{(4m_p)(2e)}{(m_p)(e)}} = \sqrt{8} = 2\sqrt{2}$. The ratio is $2\sqrt{2}:1$. Therefore, correct answer is D.