Rydberg given the equation for all visible radiation in the hydrogen spectrum as . The value of in t — Atomic Structure Chemistry Question

💡 Solution & Explanation

For the visible (Balmer) series, $\frac{1}{\lambda} = R\left(\frac{1}{2^2} - \frac{1}{n^2}\right) = R\left(\frac{n^2 - 4}{4n^2}\right)$. Thus, $\lambda = \frac{4n^2}{R(n^2 - 4)}$. Comparing this with $\lambda = \frac{kn^2}{n^2 - 4}$, we get $k = \frac{4}{R}$. Therefore, correct answer is C.