According to Maxwell's theory of electrodynamics, an electron going in a circle should emit radiatio β Atomic Structure Chemistry Question
Question
According to Maxwell's theory of electrodynamics, an electron going in a circle should emit radiation of frequency equal to its frequency of revolution. What should be the wavelength of the radiation emitted by a hydrogen atom in the ground state if this rule is followed?
Answer: C
π‘ Solution & Explanation
Frequency of revolution $f = \frac{v}{2\pi r} = \frac{2.18 \times 10^6}{2\pi \times 0.529 \times 10^{-10}} \approx 6.56 \times 10^{15}$ Hz. Wavelength $\lambda = \frac{c}{f} = \frac{3 \times 10^8}{6.56 \times 10^{15}} \approx 4.57 \times 10^{-8}$ m $\approx 45$ nm. Therefore, correct answer is C.
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