The time period of revolution in the third orbit of Li ion is second. The time period of revolution — Atomic Structure Chemistry Question

💡 Solution & Explanation

Time period $T \propto \frac{n^3}{Z^2}$. For Li$^{2+}$ ($n=3, Z=3$), $T_1 \propto \frac{3^3}{3^2} = 3 = x$. For He$^+$ ($n=2, Z=2$), $T_2 \propto \frac{2^3}{2^2} = 2$. Therefore, $T_2 = \frac{2}{3} T_1 = \frac{2}{3} x$ s. Therefore, correct answer is C.