Which of the following graphs is correct for the photoelectric effect? [Image Description: Four grap — Atomic Structure Chemistry Question
Question
Which of the following graphs is correct for the photoelectric effect? [Image Description: Four graphs (a), (b), (c), (d) of frequency $v$ on y-axis vs K.E. of Emitted Electrons on x-axis. (a) is a horizontal line. (b) is a straight line with a positive intercept on the v-axis. (c) is a straight line passing through the origin. (d) is a straight line with a negative slope.]
Answer: B
💡 Solution & Explanation
The photoelectric equation is $K.E. = h\nu - W$, which can be rearranged as $\nu = \frac{K.E.}{h} + \frac{W}{h}$. This represents a straight line with a positive slope ($1/h$) and a positive intercept on the frequency ($\nu$) axis ($W/h$). Graph (b) matches this description. Therefore, correct answer is B.
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