If is the threshold wavelength for photoelectric emission from a metal surface, is the wavelength of — Atomic Structure Chemistry Question
Question
If $\lambda_0$ is the threshold wavelength for photoelectric emission from a metal surface, $\lambda$ is the wavelength of light falling on the surface of metal and $m$ is the mass of electron, then the maximum speed of ejected electrons is given by
Answer: C
💡 Solution & Explanation
Maximum kinetic energy $\frac{1}{2}mv^2 = \frac{hc}{\lambda} - \frac{hc}{\lambda_0} = hc \left( \frac{\lambda_0 - \lambda}{\lambda_0 \lambda} \right)$. Solving for maximum speed $v$, we get $v = \left[ \frac{2hc}{m} \left( \frac{\lambda_0 - \lambda}{\lambda_0 \lambda} \right) \right]^{1/2}$. Therefore, correct answer is C.
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