Light of wavelength, , strikes a metal surface with intensity and the metal emits electrons per seco β Atomic Structure Chemistry Question
Question
Light of wavelength, $\lambda$, strikes a metal surface with intensity $X$ and the metal emits $Y$ electrons per second of maximum kinetic energy $Z$. What will happen to $Y$ and $Z$ if $X$ is halved?
Answer: C
π‘ Solution & Explanation
The number of photoelectrons emitted ($Y$) is directly proportional to the intensity ($X$) of the incident light. If intensity is halved, $Y$ is halved. The maximum kinetic energy ($Z$) depends only on the wavelength and is independent of intensity, so $Z$ remains the same. Therefore, correct answer is C.
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