The dissociation energy of H is 429.0 kJ/mol. If H is dissociated by illumination with radiation of — Atomic Structure Chemistry Question

💡 Solution & Explanation

Total radiant energy provided per mole $= \frac{N_A hc}{\lambda} = \frac{6 \times 10^{23} \times 6.6 \times 10^{-34} \times 3 \times 10^8}{270 \times 10^{-9}} = 440 \times 10^3$ J/mol $= 440$ kJ/mol. Energy used for kinetic energy $= 440 - 429 = 11$ kJ/mol. Percentage converted $= \frac{11}{440} \times 100 = 2.5\%$. Therefore, correct answer is B.