O undergoes photochemical dissociation into one normal oxygen atom and one oxygen atom, 1.2 eV more — Atomic Structure Chemistry Question
Question
O$_2$ undergoes photochemical dissociation into one normal oxygen atom and one oxygen atom, 1.2 eV more energetic than normal. The dissociation of O$_2$ into two normal atoms of oxygen requires 482.5 kJ/mol. The maximum wavelength effective for photochemical dissociation of O$_2$ is (1 eV = 96.5 kJ/mol)
Answer: D
💡 Solution & Explanation
Dissociation energy into two normal atoms per molecule $= \frac{482.5 \text{ kJ/mol}}{96.5 \text{ kJ/mol/eV}} = 5.0$ eV. Total required energy $= 5.0 \text{ eV (for dissociation)} + 1.2 \text{ eV (extra excitation)} = 6.2$ eV. The maximum wavelength $\lambda = \frac{1240}{6.2} \approx 200$ nm. Therefore, correct answer is D.
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