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At one time the meter was defined as 1650763.73 wavelength of the orange light emitted by a light soAtomic Structure Chemistry Question

Question

At one time the meter was defined as 1650763.73 wavelength of the orange light emitted by a light source containing Kr$^{86}$ atoms. What is the corresponding photon energy of this radiation?

Answer: A

💡 Solution & Explanation

The wavelength $\lambda = \frac{1 \text{ m}}{1650763.73} \approx 6.057 \times 10^{-7}$ m. Energy of one photon $E = \frac{hc}{\lambda} = \frac{6.626 \times 10^{-34} \times 3 \times 10^8}{6.057 \times 10^{-7}} \approx 3.28 \times 10^{-19}$ J. Therefore, correct answer is A.

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