At one time the meter was defined as 1650763.73 wavelength of the orange light emitted by a light so — Atomic Structure Chemistry Question
Question
At one time the meter was defined as 1650763.73 wavelength of the orange light emitted by a light source containing Kr$^{86}$ atoms. What is the corresponding photon energy of this radiation?
Answer: A
💡 Solution & Explanation
The wavelength $\lambda = \frac{1 \text{ m}}{1650763.73} \approx 6.057 \times 10^{-7}$ m. Energy of one photon $E = \frac{hc}{\lambda} = \frac{6.626 \times 10^{-34} \times 3 \times 10^8}{6.057 \times 10^{-7}} \approx 3.28 \times 10^{-19}$ J. Therefore, correct answer is A.
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