The dye acriflavine when dissolved in water has its maximum light absorption at 4530 Å and has maxim — Atomic Structure Chemistry Question

💡 Solution & Explanation

$E_{abs} = n_a \frac{hc}{\lambda_a}$ and $E_{em} = n_e \frac{hc}{\lambda_e}$. Given $n_e = 0.53 n_a$. Efficiency percentage $= \frac{E_{em}}{E_{abs}} \times 100 = \frac{n_e}{n_a} \times \frac{\lambda_a}{\lambda_e} \times 100 = 0.53 \times \frac{4530}{5080} \times 100 \approx 47.2\%$. Therefore, correct answer is B.