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A certain laser transition emits quanta per sec per square metre of nm. What is the power output in Atomic Structure Chemistry Question

Question

A certain laser transition emits $6.0 \times 10^{15}$ quanta per sec per square metre of $\lambda = 662.6$ nm. What is the power output in joule per sec per square metre?

Answer: A

💡 Solution & Explanation

Power output = Energy emitted per second. $P = n \times \frac{hc}{\lambda} = 6.0 \times 10^{15} \times \frac{6.626 \times 10^{-34} \times 3 \times 10^8}{662.6 \times 10^{-9}} = 6.0 \times 10^{15} \times 3 \times 10^{-19} = 18 \times 10^{-4} = 1.8 \times 10^{-3}$ J/(s·m$^2$). Therefore, correct answer is A.

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