The mass of a negative meson is 208 time the mass of electron. If ratio of -particle is unit, the ra — Atomic Structure Chemistry Question

💡 Solution & Explanation

For $\alpha$-particle, $(e/m)_\alpha = \frac{2e}{4m_p} = \frac{e}{2m_p} = x$. For the meson, charge is $e$ and mass is $208m_e$. The proton mass $m_p \approx 1836 m_e$. The meson's specific charge is $\frac{e}{208m_e}$. The ratio is $\frac{e/(208m_e)}{e/(2m_p)} = \frac{2m_p}{208m_e} = \frac{2 \times 1836}{208} \approx 17.65$. Thus, it is $17.65x$. Therefore, correct answer is C.