Specific charges of two particles A and B are in the ratio 2:3. If the mass ratio, is 2:3, then the — Atomic Structure Chemistry Question

💡 Solution & Explanation

Specific charge is given by $e/m$. We are given $(e_A/m_A) / (e_B/m_B) = 2/3$. This simplifies to $(e_A/e_B) \times (m_B/m_A) = 2/3$. Since $m_A/m_B = 2/3$, we have $m_B/m_A = 3/2$. Substituting this yields $(e_A/e_B) \times (3/2) = 2/3 \implies e_A/e_B = 4/9$. Therefore, correct answer is B.