The charge on the electron and proton is reduced to half. Let the present value of the Rydberg const — Atomic Structure Chemistry Question

💡 Solution & Explanation

The Rydberg constant $R$ is proportional to $e^4$. If the charge is halved ($e/2$), the new constant becomes proportional to $(e/2)^4 = e^4/16$. Thus, the new value is $R/16$. Therefore, correct answer is D.