Suppose that means were available for stripping 29 electrons from in vapours of this metal. The ioni — Atomic Structure Chemistry Question

💡 Solution & Explanation

The last electron remaining forms a hydrogen-like ion with $Z=30$. The ionization energy is $I.E. = 13.6 Z^2 = 13.6 \times (30)^2 = 13.6 \times 900 = 12240$ eV, which is $12.24$ keV. Therefore, correct answer is B.