Suppose that means were available for stripping 29 electrons from in vapours of this metal. The ioni — Atomic Structure Chemistry Question
Question
Suppose that means were available for stripping 29 electrons from $_{30}\text{Zn}$ in vapours of this metal. The ionization energy for the last electron is
Answer: B
💡 Solution & Explanation
The last electron remaining forms a hydrogen-like ion with $Z=30$. The ionization energy is $I.E. = 13.6 Z^2 = 13.6 \times (30)^2 = 13.6 \times 900 = 12240$ eV, which is $12.24$ keV. Therefore, correct answer is B.
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