The ionization energy of ion is eV. The ionization energy of ion should be — Atomic Structure Chemistry Question

💡 Solution & Explanation

Ionization energy is proportional to $Z^2$. For $\text{He}^+$ ($Z=2$), $I.E. \propto 4 = x$. For $\text{Be}^{3+}$ ($Z=4$), $I.E. \propto 16$. The ratio is $16/4 = 4$, so the ionization energy is $4x$. Therefore, correct answer is A.