How much energy is needed for an electron revolving in the second orbit of ion, in order double its — Atomic Structure Chemistry Question

💡 Solution & Explanation

Initial state $n_1 = 2$. Doubling the angular momentum ($L \propto n$) means moving to $n_2 = 4$. The energy required is $\Delta E = 13.6 \times 2^2 \times (\frac{1}{2^2} - \frac{1}{4^2}) = 54.4 \times (\frac{1}{4} - \frac{1}{16}) = 10.2$ eV. Therefore, correct answer is C.