As the orbit number increases, the difference in two consecutive energy levels — Atomic Structure Chemistry Question

💡 Solution & Explanation

Energy of $n^{th}$ orbit is $E_n \propto -\frac{1}{n^2}$. The difference $\Delta E = E_{n+1} - E_n \propto \frac{1}{n^2} - \frac{1}{(n+1)^2}$, which becomes smaller as $n$ increases. Therefore, correct answer is C.