The threshold wavelength for ejection of electrons from a metal is 330 nm. The work function for the — Atomic Structure Chemistry Question

💡 Solution & Explanation

Work function $W = \frac{hc}{\lambda_0} = \frac{6.6 \times 10^{-34} \times 3 \times 10^8}{330 \times 10^{-9}} = \frac{19.8 \times 10^{-26}}{330 \times 10^{-9}} = 0.06 \times 10^{-17} = 6.0 \times 10^{-19}$ J. Therefore, correct answer is B.