A photo sensitive surface is receiving light of wavelength 5000 Γ at the rate of J/s. The number of β Atomic Structure Chemistry Question
Question
A photo sensitive surface is receiving light of wavelength 5000 Γ at the rate of $10^{-7}$ J/s. The number of photons received per second is
Answer: A
π‘ Solution & Explanation
Energy of one photon $E = \frac{hc}{\lambda} = \frac{6.626 \times 10^{-34} \times 3 \times 10^8}{5000 \times 10^{-10}} \approx 3.975 \times 10^{-19}$ J. Number of photons per second $n = \frac{\text{Power}}{E} = \frac{10^{-7}}{3.975 \times 10^{-19}} \approx 2.5 \times 10^{11}$. Therefore, correct answer is A.
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