Radiations of frequency, , are incident on a photosensitive metal. The maximum kinetic energy of pho — Atomic Structure Chemistry Question
Question
Radiations of frequency, $\nu$, are incident on a photosensitive metal. The maximum kinetic energy of photoelectrons is $E$. When the frequency of the incident radiations is doubled, what is the maximum kinetic energy of the photoelectrons?
Answer: C
💡 Solution & Explanation
Initial state: $E = h\nu - W$. Final state with frequency $2\nu$: $E' = h(2\nu) - W = 2h\nu - W = h\nu + (h\nu - W) = h\nu + E$. Therefore, correct answer is C.
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