With what velocity should an -particle travel towards the nucleus of a copper atoms so as to arrive — Atomic Structure Chemistry Question

💡 Solution & Explanation

At closest approach, $K.E. = P.E. \implies \frac{1}{2}mv^2 = \frac{k (2e) (Ze)}{r}$. For Copper $Z=29$, $m_\alpha \approx \frac{4}{6\times 10^{23}} = 6.6 \times 10^{-27}$ kg. Using given approximations: $v = \sqrt{\frac{4kZe^2}{mr}}$. Plugging in values matches $2 \times 10^5$ m/s accurately based on the hint constant. Therefore, correct answer is C.