In the different experiments, -particles, proton, deuteron and neutron are projected towards gold nu — Atomic Structure Chemistry Question

💡 Solution & Explanation

Distance of closest approach $r_0 = \frac{kQq}{K.E.} \propto q$. A neutron carries no charge ($q=0$), meaning there is no electrostatic repulsion. Hence, its theoretical distance of closest approach drops to zero (it directly hits the nucleus). Therefore, correct answer is D.