Two particles, A and B, having same ratio are projected towards silver nucleus, in different experim — Atomic Structure Chemistry Question

💡 Solution & Explanation

Distance of closest approach $r_0 = \frac{kQq}{1/2 mv^2} = \frac{2kQ}{v^2} \left(\frac{q}{m}\right)$. Since both speed $v$ and specific charge $e/m$ (or $q/m$) are the same, $r_0$ will be the same for both particles. Therefore, correct answer is A.