If the nitrogen atom has electronic configuration , it would have energy lower than that of the normal ground state configuration , because the electrons would be closer to the nucleus. Yet is not obs

Question

If the nitrogen atom has electronic configuration $1s^7$, it would have energy lower than that of the normal ground state configuration $1s^2 2s^2 2p^3$, because the electrons would be closer to the nucleus. Yet $1s^7$ is not observed because it violates

Prashant Kotian · Accepted Answer

Correct answer: C. Pauli's exclusion principle limits the maximum number of electrons in an s-orbital to 2 (since there are only 2 spin states). Having 7 electrons in the 1s orbital strictly violates this principle. Therefore, correct answer is C.

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