If the numbers of orbitals of a particular type were , but spin quantum numbers were only +1/2 and – — Atomic Structure Chemistry Question

💡 Solution & Explanation

For d-type orbitals, $l=2$. The hypothetical number of orbitals would be $3(2) + 1 = 7$. Since each orbital can hold 2 electrons (spin +1/2, -1/2), the maximum capacity is $7 \times 2 = 14$ electrons. Therefore, correct answer is B.