If there are three possible values (–1/2, 0, +1/2) for the spin quantum number, then the maximum cap — Atomic Structure Chemistry Question

💡 Solution & Explanation

Second orbit ($n=2$) has 4 orbitals (one 2s and three 2p orbitals). If each orbital can hold 3 electrons (due to 3 allowed spin states), the maximum capacity is $4 \times 3 = 12$ electrons. Therefore, correct answer is C.