The number of orbitals having is — Atomic Structure Chemistry Question

💡 Solution & Explanation

Possible orbitals with $n+l < 5$ are: 1s ($1+0=1$, 1 orbital), 2s ($2+0=2$, 1 orbital), 2p ($2+1=3$, 3 orbitals), 3s ($3+0=3$, 1 orbital), 3p ($3+1=4$, 3 orbitals), 4s ($4+0=4$, 1 orbital). Total orbitals = $1+1+3+1+3+1 = 10$. Therefore, correct answer is D.