The orbital angular momentum of a 4p electron will be — Atomic Structure Chemistry Question

💡 Solution & Explanation

The formula for orbital angular momentum is $L = \sqrt{l(l+1)}\frac{h}{2\pi}$. For any p-orbital, the azimuthal quantum number $l=1$. Thus, $L = \sqrt{1(1+1)}\frac{h}{2\pi} = \sqrt{2}\frac{h}{2\pi}$. Therefore, correct answer is B.