The momentum of a photon of wavelength 6626 nm will be — Atomic Structure Chemistry Question

💡 Solution & Explanation

The momentum of a photon is given by $p = \frac{h}{\lambda}$. Substituting values gives $p = \frac{6.626 \times 10^{-34} \text{ J s}}{6626 \times 10^{-9} \text{ m}} = \frac{6.626 \times 10^{-34}}{6.626 \times 10^{-6}} = 10^{-28} \text{ kg m s}^{-1}$. Therefore, correct answer is A.