An electron makes five crests during one revolution round H-nucleus. The electron belongs from the — Atomic Structure Chemistry Question

💡 Solution & Explanation

According to Bohr's orbit quantization via de-Broglie wave theory, $2\pi r = n\lambda$. The number of wavelengths (crests) formed in one complete revolution is equal to the principal quantum number $n$. Thus, $n = 5$, indicating the fifth orbit. Therefore, correct answer is C.