The wavelength of radiation emitted out in the transition to in ion is — Atomic Structure Chemistry Question

💡 Solution & Explanation

By Rydberg formula, $\frac{1}{\lambda} = R Z^2 \left(\frac{1}{n_1^2} - \frac{1}{n_2^2}\right)$. For $Li^{2+}$, $Z=3$, so $\frac{1}{\lambda} = R (3)^2 \left(\frac{1}{1^2} - \frac{1}{4^2}\right) = 9R \left(1 - \frac{1}{16}\right) = 9R \left(\frac{15}{16}\right) = \frac{135 R}{16}$. Therefore, $\lambda = \frac{16}{135 R}$. Therefore, correct answer is B.