The magnitude of spin angular momentum of an electron is given by — Atomic Structure Chemistry Question

💡 Solution & Explanation

The magnitude of spin angular momentum is given by $\sqrt{s(s+1)}\frac{h}{2\pi}$. For an electron, $s = \frac{1}{2}$, so the magnitude is $\sqrt{\frac{1}{2}(\frac{3}{2})}\frac{h}{2\pi} = \frac{\sqrt{3}}{2}\frac{h}{2\pi}$. Therefore, correct answer is A, C.