An electron beam can undergo diffraction by crystals. Through what potential (in Volt) should a beam — Atomic Structure Chemistry Question

💡 Solution & Explanation

The de-Broglie wavelength of an electron accelerated through a potential difference $V$ is given by $\lambda = \frac{1.227}{\sqrt{V}}$ nm. Substituting the given wavelength: $0.25 = \frac{1.227}{\sqrt{V}} \implies \sqrt{V} = \frac{1.227}{0.25} = 4.908$. Squaring both sides gives $V = (4.908)^2 \approx 24.08$ V. Rounding to the nearest integer yields 24 V. Therefore, correct answer is 0024.