The Schrodinger wave equation for hydrogen atom is:
, where is Bohr's radius. If the radial node is 2s be at , then the value of is

Question

The Schrodinger wave equation for hydrogen atom is:
$\Psi_{2s} = \frac{1}{4\sqrt{2\pi}} \left(\frac{1}{a_0}\right)^{3/2} \left(2 - \frac{r}{a_0}\right) e^{-r/2a_0}$, where $a_o$ is Bohr's radius. If the radial node is 2s be at $r_0$, then the value of $r_0/a_0$ is

Prashant Kotian · Accepted Answer

Correct answer: 2. A radial node occurs where the radial probability distribution goes to zero, which means the wave function equals zero. Setting the polynomial part to zero: , which gives . Therefore, correct answer is 2.

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