The Schrodinger wave equation for hydrogen atom is:<br>, where is Bohr's radius. If the radial node — Atomic Structure Chemistry Question
Question
The Schrodinger wave equation for hydrogen atom is:<br>$\Psi_{2s} = \frac{1}{4\sqrt{2\pi}} \left(\frac{1}{a_0}\right)^{3/2} \left(2 - \frac{r}{a_0}\right) e^{-r/2a_0}$, where $a_o$ is Bohr's radius. If the radial node is 2s be at $r_0$, then the value of $r_0/a_0$ is
Answer: 2
💡 Solution & Explanation
A radial node occurs where the radial probability distribution goes to zero, which means the wave function $\Psi$ equals zero. Setting the polynomial part to zero: $2 - \frac{r_0}{a_0} = 0$, which gives $\frac{r_0}{a_0} = 2$. Therefore, correct answer is 2.
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