The orbital angular momentum quantum number of the state is — Atomic Structure Chemistry Question

💡 Solution & Explanation

State $S_2$ has energy equal to ground state of H. $E_{S2} = -13.6 \frac{3^2}{n^2} = -13.6 \implies n^2 = 9 \implies n=3$. It has 1 radial node: $n - l - 1 = 1 \implies 3 - l - 1 = 1 \implies l = 1$. The orbital angular momentum quantum number $l$ is 1. Therefore, correct answer is B.