What is the minimum energy of the photons emitted by this atom during de-excitation? — Atomic Structure Chemistry Question

💡 Solution & Explanation

Minimum energy is emitted during a transition between adjacent highest available energy levels. For this atom starting at $n=8$, the minimum energy transition is $8 \to 7$. $E_{8\to7} = 13.6 \times 8^2 \times (1/49 - 1/64) = 870.4 \times \frac{15}{3136} \approx 4.16$ eV. Therefore, correct answer is B.