The ionization energy for gas atoms is — Atomic Structure Chemistry Question

💡 Solution & Explanation

As shown in the previous derivation, the transition $n=2 \to 4$ takes 2.7 eV. $\Delta E = I.E. \times (\frac{1}{4} - \frac{1}{16}) = I.E. \times \frac{3}{16} = 2.7 \implies I.E. = \frac{2.7 \times 16}{3} = 14.4$ eV. Therefore, correct answer is C.