How much energy will be emitted when an electron in this atom moves from to ground state? — Atomic Structure Chemistry Question

💡 Solution & Explanation

Since $n=6$, $n+1 = 7$. Energy from $n=7$ to ground state ($n=1$) is $\Delta E = 13.6 \times 3^2 \times (\frac{1}{1^2} - \frac{1}{7^2}) = 122.4 \times (1 - \frac{1}{49}) = 122.4 \times \frac{48}{49} \approx 119.9$ eV. Therefore, correct answer is C.