The speed of electron in the orbit is — Atomic Structure Chemistry Question

💡 Solution & Explanation

Substitute $r$ back into $v = \frac{nh}{2\pi mr}$: $v = \frac{nh}{2\pi m \left(\frac{4\pi \sqrt{km}}{nh}\right)} = \frac{n^2 h^2}{8\pi^2 m \sqrt{km}}$. Therefore, correct answer is D.