At 70 K, the adsorption of N₂(g) at iron surface obeys Freundlich adsorption isotherm. The following data is collected experimentally: P (/bar) = 4, 25, 64 and corresponding x/m = 0.2, 0.5, 0.8 respec

Question

At 70 K, the adsorption of N₂(g) at iron surface obeys Freundlich adsorption isotherm. The following data is collected experimentally: P (/bar) = 4, 25, 64 and corresponding x/m = 0.2, 0.5, 0.8 respectively, where x/m is the mass (in g) of N₂(g) adsorbed per g of iron at P bar pressure. The moles of N₂(g) adsorbed per g iron at 36 bar and 70 K is

Prashant Kotian · Accepted Answer

Correct answer: B. Using x/m = kP^(1/n): 0.2 = k(4)^(1/n) and 0.8 = k(64)^(1/n). Dividing them, 4 = 16^(1/n), so 1/n = 1/2. Substituting back, 0.2 = k(4)^(1/2) = 2k, so k = 0.1. At P = 36 bar, x/m = 0.1 × (36)^(1/2) = 0.6 g. Moles of N₂ = Mass / Molar mass = 0.6 / 28 = 6 / 280 = 3/140. Therefore, correct answer is B.

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