Graph between log (x/m) and log P is a straight line at an angle 45° with intercept on y-axis, 0.3010. The amount (in g) of the gas absorbed per g of the adsorbent when pressure is 0.2 atm, is (assume

Question

Graph between log (x/m) and log P is a straight line at an angle 45° with intercept on y-axis, 0.3010. The amount (in g) of the gas absorbed per g of the adsorbent when pressure is 0.2 atm, is (assume that the adsorption obey Freundlich isotherm)

Prashant Kotian · Accepted Answer

Correct answer: A. According to Freundlich isotherm, log(x/m) = log k + (1/n)log P. The slope 1/n = tan(45°) = 1, so n = 1. Intercept log k = 0.3010, so k = 2. Then, x/m = k(P)^(1/n) = 2 × (0.2)^1 = 0.4 g. Therefore, correct answer is A.

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