Surface ChemistryhardINTEGER

The ΔH of adsorption at constant amount of vapour adsorbed is called the isosteric enthalpy of adsorSurface Chemistry Chemistry Question

Question

The ΔH of adsorption at constant amount of vapour adsorbed is called the isosteric enthalpy of adsorption, ΔₐH. The adsorption of N₂ on charcoal amounted to 0.894 cm³ (STP)/g at (0.4 atm and 200 K) and (at 59.2 atm and T K). If ΔₐH = –16.628 kJ/mol, then the value of T is

Answer: 0400

💡 Solution & Explanation

The Clausius-Clapeyron equation for an isostere gives ln(P₂/P₁) = (-ΔₐH/R) (1/T₁ - 1/T₂). Here, P₁ = 0.4 atm at T₁ = 200 K, and P₂ = 59.2 atm at T₂ = T. ΔₐH = -16.628 kJ/mol = -16628 J/mol, and R = 8.314 J/(mol·K). ln(59.2 / 0.4) = ln(148) ≈ 5.0. 5.0 = (-(-16628)/8.314) × (1/200 - 1/T) = 2000 × (0.005 - 1/T). 0.0025 = 0.005 - 1/T, which simplifies to 1/T = 0.0025. T = 1 / 0.0025 = 400 K. Therefore, correct answer is 0400.

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