It was found that 0.10 mg of an adsorbate covered 0.06 m² of a solid surface. If the molar mass of t — Surface Chemistry Chemistry Question

💡 Solution & Explanation

Mass of adsorbate = 0.10 mg = 1.0 × 10⁻⁴ g. Molar mass = 0.25 kg/mol = 250 g/mol. Moles of adsorbate = (1.0 × 10⁻⁴) / 250 = 4.0 × 10⁻⁷ mol. Number of molecules = Moles × N_A = 4.0 × 10⁻⁷ × 6.0 × 10²³ = 2.4 × 10¹⁷ molecules. Total surface area covered = 0.06 m². Effective area per molecule = 0.06 m² / (2.4 × 10¹⁷ molecules) = 0.025 × 10⁻¹⁷ m² = 25 × 10⁻²⁰ m². The value in 10⁻²⁰ m² is 25. Therefore, correct answer is 0025.