Surface ChemistryhardINTEGER

The desorption of gas molecules from the adsorbent surface obeys Arrhenius equation. The average timSurface Chemistry Chemistry Question

Question

The desorption of gas molecules from the adsorbent surface obeys Arrhenius equation. The average time (in sec) up to which a N₂ molecule may remain adsorbed at Pt-surface at 400 K is (Arrhenius parameters for desorption are: A = 1.25 × 10⁸ s⁻¹, Eₐ = 16 kcal/mol; e²⁰ = 5 × 10⁸)

Answer: 4

💡 Solution & Explanation

The rate constant for desorption is given by the Arrhenius equation: k = A·e^(-Eₐ/RT). Here, Eₐ = 16 kcal/mol = 16000 cal/mol, R = 2 cal/(mol·K), and T = 400 K. So, Eₐ/RT = 16000 / (2 × 400) = 20. Thus, k = 1.25 × 10⁸ × e⁻²⁰. Given e²⁰ = 5 × 10⁸, e⁻²⁰ = 1 / (5 × 10⁸). Substituting this, k = (1.25 × 10⁸) / (5 × 10⁸) = 1.25 / 5 = 0.25 s⁻¹. The average time of residence τ is the reciprocal of the rate constant: τ = 1/k = 1/0.25 = 4 s. Therefore, correct answer is 4.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry