Rate of an uncatalysed first-order reaction at T K is half of the rate of catalysed reaction at '0.5 — Chemical Kinetics Chemistry Question
Question
Rate of an uncatalysed first-order reaction at T K is half of the rate of catalysed reaction at '0.5T' K. If the catalyst lowers the threshold energy by 20 kcal, what is the activation energy of uncatalysed reaction? (T = 300 K, ln 2 = 0.7)
Answer: A
💡 Solution & Explanation
k_uncat(T) = 0.5 k_cat(0.5T). A e^(-Ea / RT) = 0.5 A e^(-(Ea - 20) / R(0.5T)). Simplifying gives e^((Ea - 40)/RT) = 0.5, so (Ea - 40)/RT = -ln 2. Ea = 40 - RT ln 2. At 300K, RT ln 2 = (2 cal/K*mol)(300 K)(0.7) = 420 cal/mol = 0.42 kcal/mol. Ea = 40 - 0.42 = 39.58 kcal/mol. Therefore, correct answer is A.
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