For the consecutive first-order reactions: A → B → C, B is in steady state. What will be the concentration of C at this stage? At t = 0, [A] = [A]0 and [B] = [C] = 0.

Question

Prashant Kotian · Accepted Answer

Correct answer: C. Because B is in a steady state, its concentration remains very small and approximately constant. By mass balance, [A]0 = [A] + [B] + [C] ≈ [A] + [C]. Thus [C] ≈ [A]0 - [A] = [A]0 - [A]0 e^-K1t = [A]0 (1 - e^-K1t). Therefore, correct answer is C.

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