For the consecutive first-order reactions: A → B → C, the concentrations of A and B are 0.2 M and 0.01 M, respectively, at steady state. If K1 is 2.5 × 10^-4 min^-1, what is the value of K2?

Question

Prashant Kotian · Accepted Answer

Correct answer: A. At steady state for B, d[B]/dt = K1[A] - K2[B] = 0. Thus, K2 = K1[A]/[B] = (2.5 × 10^-4) × (0.2 / 0.01) = 5.0 × 10^-3 min^-1. Therefore, correct answer is A.

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